我已经想出一个办法来表达 a.b[c.d][e].f[g[h[i.j]]]
用我自己的树格式。 这表达,表示作为一棵树上,看起来是这样的:
{
"form": "nest",
"link": [
{
"form": "site",
"name": "a"
},
{
"form": "site",
"name": "b"
},
{
"form": "nest",
"link": [
{
"form": "site",
"name": "c"
},
{
"form": "site",
"name": "d"
}
]
},
{
"form": "nest",
"link": [
{
"form": "site",
"name": "e"
}
]
},
{
"form": "site",
"name": "f"
},
{
"form": "nest",
"link": [
{
"form": "site",
"name": "g"
},
{
"form": "nest",
"link": [
{
"form": "site",
"name": "h"
},
{
"form": "nest",
"link": [
{
"form": "site",
"name": "i"
},
{
"form": "site",
"name": "j"
}
]
}
]
}
]
}
]
}
现在,同样的串的表达,也是由此JS AST树形结构 MemberExpression
:
{
"type": "MemberExpression",
"object": {
"type": "MemberExpression",
"object": {
"type": "MemberExpression",
"object": {
"type": "MemberExpression",
"object": {
"type": "MemberExpression",
"object": {
"type": "Identifier",
"name": "a"
},
"property": {
"type": "Identifier",
"name": "b"
},
"computed": false
},
"property": {
"type": "MemberExpression",
"object": {
"type": "Identifier",
"name": "c"
},
"property": {
"type": "Identifier",
"name": "d"
},
"computed": false
},
"computed": true
},
"property": {
"type": "Identifier",
"name": "e"
},
"computed": true
},
"property": {
"type": "Identifier",
"name": "f"
},
"computed": false
},
"property": {
"type": "MemberExpression",
"object": {
"type": "Identifier",
"name": "g"
},
"property": {
"type": "MemberExpression",
"object": {
"type": "Identifier",
"name": "h"
},
"property": {
"type": "MemberExpression",
"object": {
"type": "Identifier",
"name": "i"
},
"property": {
"type": "Identifier",
"name": "j"
},
"computed": false
},
"computed": true
},
"computed": true
},
"computed": true
}
所以 这两个树的结构表示同样的串表情 a.b[c.d][e].f[g[h[i.j]]]
. 你会发现第一个"鸟巢"的结构,有两种类型的目的、网站和巢穴。 一个的网站只是一个名字,同时巢意味着一个"计算"的财产在JS AST术语。 因此,一个鸟巢是喜欢 parent[this_is_a_nest[and_another_nest]]
同时 parent.site1.site2
.
你如何改变第一棵树的结构进入第二个吗?
什么我有这么远远不是真正到那里,这是很令人困惑。
console.log(JSON.stringify(transform(getNest()), null, 2))
function transform(nest) {
let i = 0
let stack = []
while (i < nest.link.length) {
let object = nest.link[i++]
let property = nest.link[i]
let member = {
type: 'MemberExpression'
}
stack.push(member)
if (object.form === 'nest') {
member.object = transform(object)
} else {
member.object = {
type: 'Identifier',
name: object.name
}
}
if (property) {
if (property.form === 'nest') {
member.property = transform(property)
member.computed = true
} else {
member.property = {
type: 'Identifier',
name: property.name
}
}
}
}
let object = stack.pop()
while (stack.length) {
let nextObject = stack.pop()
nextObject.object = object
object = nextObject
}
return object
}
function getNest() {
return {
"form": "nest",
"link": [
{
"form": "site",
"name": "a"
},
{
"form": "site",
"name": "b"
},
{
"form": "nest",
"link": [
{
"form": "site",
"name": "c"
},
{
"form": "site",
"name": "d"
}
]
},
{
"form": "nest",
"link": [
{
"form": "site",
"name": "e"
}
]
},
{
"form": "site",
"name": "f"
},
{
"form": "nest",
"link": [
{
"form": "site",
"name": "g"
},
{
"form": "nest",
"link": [
{
"form": "site",
"name": "h"
},
{
"form": "nest",
"link": [
{
"form": "site",
"name": "i"
},
{
"form": "site",
"name": "j"
}
]
}
]
}
]
}
]
}
}
真的不知道如何简化该问题的方式解决它。
我不知道如果 这 是任何帮助(acornjs parser for成员).