在这个查询*我名单和排序的行"mytableabc"的纬度、经度、各种标准,...从附近或远或分及其工作/清单数据,并且我认为其良好的/足够多快!?
select
round((6371 * acos(cos(radians('40.123456')) * cos(radians(latitude)) * cos(radians(longtitude) - radians('29.123456')) + sin(radians(latitude)) * sin(radians('40.123456')))), (2)) as distance,
(match(colone,coltwo) against('searchkeywordabc' in boolean mode)) as score,
id,colone,coltwo,latitude,longtitude,colthree
from mytableabc
where (colone='sampleforsomething')
and (match(colone,coltwo) against('searchkeywordabc' in boolean mode))
having distance <= 5 order by distance asc limit 0,50
--问题
在不同的线路和文件,我仅仅需要总数数(id)的返回元用同样的标准... 我试着要添加数(id),但它没有提供正确的数总和还列出行, 我只想总数字(作为正常的数查询的确)不是数据线
select
count(id),
round((6371 * acos(cos(radians('40.123456')) * cos(radians(latitude)) * cos(radians(longtitude) - radians('29.123456')) + sin(radians(latitude)) * sin(radians('40.123456')))), (2)) as distance,
(match(colone,coltwo) against('searchkeywordabc' in boolean mode)) as score,
id,colone,coltwo,latitude,longtitude,colthree
from mytableabc
where (colone='sampleforsomething')
and (match(colone,coltwo) against('searchkeywordabc' in boolean mode))
having distance <= 5 order by distance asc limit 0,50
--还有这个查询,而无需的距离/纬度/longtitude标准运作良好,只返回总数的...但是我需要加入距离查询,查询这个
select count(id) from mytableabc where (colone='sampleforsomething') and (match(colone,coltwo) against('searchkeywordabc' in boolean mode))
我不sql专家是正如你看到的我需要一个。 谢谢你。