加务(如果不是已经存在)使用Bash脚本

但是，运行这个命令给的错误：

-bash: */1 * * * * some_user python /mount/share/script.py >> /root/foo/logs/foo.cron.log 2>&1: No such file or directory

代码:

(crontab -l | grep '/mount/share/script.py') || { crontab -l; '*/1 * * * * some_user python /mount/share/script.py >> /root/foo/logs/foo.cron.log 2>&1'; } | crontab -

将尝试执行/运行：

'*/1 * * * * some_user python /mount/share/script.py >> /root/foo/logs/foo.cron.log 2>&1'

如果当 grep 失败。

增加的回声在它前面的或printf，因为 crontab 预计输入从 stdin像你做了什么你的第一个例/标，是这样的：

(crontab -l | grep '/mount/share/script.py') || { crontab -l; echo '*/1 * * * * some_user python /mount/share/script.py >> /root/foo/logs/foo.cron.log 2>&1'; } | crontab -

这里是替代，这是一个完全成熟的脚本。

#!/usr/bin/env bash

cron_entry=$(crontab -l 2>&1)
is_in_cron='/mount/share/script.py'
new_cron_entry='*/1 * * * * some_user python /mount/share/script.py >> /tmp/foo/logs/foo.cron.log 2>&1'

if [[ $cron_entry != *"$is_in_cron"* ]]; then
  printf '%s\n' "$cron_entry" "$new_cron_entry" | crontab -
fi