Css3d旋转的变换(x+y)使用小鼠拖

0

的问题

我最近潜入世界css改变,并希望转div(x轴和y轴)我是能够做到这一点有2滑0至360度的范围,但现在期待着这样做有拖鼠,我有做了一个非常草率的努力,寻找建议,以解决这个问题:

jsfiddle链接试验

"use strict";

let elContainer = $('#container');
let elBox = $('#box');

$(document).ready(function() {
  $('.slider-rotate').on('input', function() {
    sliderRotate();
  });

  elContainer.mousedown(function(e) {
    initDragRotate(e);
  });

  elContainer.mousemove(function(e) {
    dragRotate(e);
  });

  elContainer.mouseup(function(e) {
    endDragRotate();
  });

});

let dragging = false;
let delta = {};

function initDragRotate(e) {
  dragging = true;
  delta = {
    x: e.pageX,
    y: e.pageY,
  };
}

function dragRotate(e) {
  if (!dragging) {
    return;
  }

  delta.x = e.pageX - delta.x;
  delta.y = e.pageY - delta.y;

  let rotateParam = '';
  rotateParam += ' rotate' + 'Y' + '(' + delta.x + 'deg)';
  rotateParam += ' rotate' + 'X' + '(' + delta.y + 'deg)';
  elBox.css('transform', rotateParam);
}

function endDragRotate() {
  if (!dragging) {
    return;
  }

  dragging = false;
}


function sliderRotate() {
  let rotateParam = '';
  $('.slider-rotate').each(function() {
    rotateParam += ' ' + getRotateParamString($(this));
  });
  elBox.css('transform', rotateParam);
}

function getRotateParamString(elClass) {
  let val = elClass.val();
  let rotateType = elClass.data('rotateType');
  let rotateParam = 'rotate' + rotateType + '(' + val + 'deg)';

  return rotateParam;
}
#container {
  background: #ccc;
  padding: 10vh;
  display: flex;
  align-items: center;
  justify-content: center;
}

#box {
  width: 30vh;
  height: 30vh;
  border: 5px solid #000;
  position: relative;
  transform-style: preserve-3d;
}

#box>div {
  position: absolute;
  left: 0;
  right: 0;
  top: 0;
  bottom: 0;
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div id="container">
  <div id="box">
    <div style="background: #f00;"></div>
    <div style="background: #0f0;"></div>
  </div>
</div>

<div id="control">
  <br>
  <label>
    x
    <input type="range" class="slider-rotate" data-rotate-type="X" min="0" max="360" value="0">
  </label>
  <br>
  <label>
    y
    <input type="range" class="slider-rotate" data-rotate-type="Y" min="0" max="360" value="0">
  </label>
</div>

此外,还有2div在顶部和底部(绿色和红色)与变换风格的保留-3d财产,希望它的其他颜色的时翻转,但没有运气! 请表明,谢谢!

css javascript jquery transform
2021-11-24 05:19:51
1

最好的答案

0

该calulation多少转动是有点奇怪。

我相信你需要的是要有旋转量依赖于数量的老鼠置于横向和纵向的屏幕。 要使这个比例到屏幕上的大小需要将它通过屏幕上的大小,然后乘以360得到充分的范围从pageX/Y正在0到正在右/屏幕底部。

"use strict";

let elContainer = $('#container');
let elBox = $('#box');

$(document).ready(function() {
  $('.slider-rotate').on('input', function() {
    sliderRotate();
  });

  elContainer.mousedown(function(e) {
    initDragRotate(e);
  });

  elContainer.mousemove(function(e) {
    dragRotate(e);
  });

  elContainer.mouseup(function(e) {
    endDragRotate();
  });

});

let dragging = false;
let delta = {};

function initDragRotate(e) {
  dragging = true;
  delta = {
    x: e.pageX,
    y: e.pageY,
  };
}

function dragRotate(e) {
  if (!dragging) {
    return;
  }
  // THIS IS THE CALCULATION THAT HAS CHANGED
  delta.x = e.pageX / window.innerWidth * 360; //- delta.x;
  delta.y = e.pageY / window.innerHeight * 360; // - delta.y;

  let rotateParam = '';
  rotateParam += ' rotate' + 'Y' + '(' + delta.x + 'deg)';
  rotateParam += ' rotate' + 'X' + '(' + delta.y + 'deg)';
  elBox.css('transform', rotateParam);
}

function endDragRotate() {
  if (!dragging) {
    return;
  }

  dragging = false;
}


function sliderRotate() {
  let rotateParam = '';
  $('.slider-rotate').each(function() {
    rotateParam += ' ' + getRotateParamString($(this));
  });
  elBox.css('transform', rotateParam);
}

function getRotateParamString(elClass) {
  let val = elClass.val();
  let rotateType = elClass.data('rotateType');
  let rotateParam = 'rotate' + rotateType + '(' + val + 'deg)';

  return rotateParam;
}
#container {
  background: #ccc;
  padding: 10vh;
  display: flex;
  align-items: center;
  justify-content: center;
}

#box {
  width: 30vh;
  height: 30vh;
  border: 5px solid #000;
  position: relative;
  transform-style: preserve-3d;
}

#box>div {
  position: absolute;
  left: 0;
  right: 0;
  top: 0;
  bottom: 0;
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div id="container">
  <div id="box">
    <div style="background: #f00;"></div>
    <div style="background: #0f0;"></div>
  </div>
</div>

<div id="control">
  <br>
  <label>
    x
    <input type="range" class="slider-rotate" data-rotate-type="X" min="0" max="360" value="0">
  </label>
  <br>
  <label>
    y
    <input type="range" class="slider-rotate" data-rotate-type="Y" min="0" max="360" value="0">
  </label>
</div>

2021-11-24 07:00:06

任何建议为什么颜色的红(div在后面)没有显示出在转动,或者我应该建立一个不同的问题是什么?
Nishu Ali

实际上它可能是更好地创建一个新的问题,因为它是一个不同的问题。
A Haworth

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