不和谐&多处理亡者开关蟒蛇

我是想让这个逻辑，所以，如果我得到的消息上的不和谐，其中包含的"911"它破坏了脚本或电话某一功能和停止计时器 im面临一个很大的错误我不能想个适当的方法来做...

任何帮助吗？

from time import sleep
import discord
import multiprocessing

client = discord.Client()
manager = multiprocessing.Manager()
sign = manager.boolean(False)

def Timer(sign):
    for second in range(15):
        if sign == True:
            print("bloooock")
            break
        if sign == False:
            print("passsssss")
            sleep(1)
def discord_message(client, sign):
    @client.event
    async def on_ready():
        print('Logged on as', client)
    async def on_message(message):
        messageContent = message.content
        if len(messageContent) > 0:
            if messageContent == str("911"):
                sign = manager.bool(True)
    client.run('###')
if __name__ == '__main__':
    freeze_support()
    p1 = multiprocessing.Process(target=Timer, args=(sign,))
    p2 = multiprocessing.Process(target=discord_message, args=(client, sign,))
    p1.start()
    p2.start()
    p1.join()
    p2.join()