PL/SQL功能返回顾客的名字给出了id

0

的问题

/创建一个PL/SQL function get_customer_name返回 客户的名字给出了ID./

/当我打电话的功能,我收到了客户的标识作为的结果。 功能应该回顾客的名称。 我是什么失踪了吗/

--Oracle PL/SQL功能:--

CREATE OR REPLACE FUNCTION get_customer_name(cust_id IN VARCHAR)
RETURN NUMBER
IS 
cname VARCHAR2 (50);
BEGIN
    SELECT customer_id INTO cname FROM s_order_t o WHERE o.order_id = cust_id;
    RETURN cname;
    EXCEPTION
    WHEN no_data_found THEN
    DBMS_OUTPUT.PUT_LINE('NO SUCH EMPLOYEE');
RETURN -1;
END;

/写一个匿名PL/SQL节目叫 这个函数的一些单标识作为输入,并且打印出来的结果。/ -能电话:--

DECLARE
cname VARCHAR2 (50);
BEGIN
    cname := get_customer_name (1010);
    DBMS_OUTPUT.PUT_LINE (cname);
END;
oracle
2021-11-23 18:52:27
1

最好的答案

0

你不是输出该客户的名字,你可能需要 JOIN 来一个 customers 表,并得到的 name 栏(假设是什么,他们被称为):

CREATE OR REPLACE FUNCTION get_customer_name(
  cust_id IN S_ORDER_T.ORDER_ID%TYPE
) RETURN CUSTOMERS.NAME%TYPE
IS 
  cname CUSTOMERS.NAME%TYPE;
BEGIN
  SELECT name
  INTO   cname
  FROM   s_order_t o
         INNER JOIN customers c
         ON (o.customer_id = c.id)
  WHERE o.order_id = cust_id;

  RETURN cname;
EXCEPTION
  WHEN no_data_found THEN
    RETURN NULL;
END;
/

对于该样本数据:

CREATE TABLE IF NOT EXISTS customers (
  id INTEGER PRIMARY KEY,
  name VARCHAR2(20)
);

CREATE TABLE IF NOT EXISTS s_order_t (
  order_id INTEGER PRIMARY KEY,
  customer_id REFERENCES customers
);

INSERT IGNORE INTO customers VALUES (1, 'Alice');
INSERT IGNORE INTO s_order_t VALUES (1010, 1);

然后:

DECLARE
  cname CUSTOMERS.NAME%TYPE;
BEGIN
  cname := get_customer_name (1010);
  DBMS_OUTPUT.PUT_LINE (cname);
END;
/

产出:

Alice

db<>的小提琴 这里

2021-11-23 21:57:59

谢谢。 它的工作与一些微小的变化。
Chuck

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