不能得到瓷砖碰撞的放[重复]

0

的问题

所以我做了一个基于成熟,我不能得到冲突的工作。

这个代码在主循环显示的瓷砖:

tile_rects = []
    y = 0
    for layer in game_map:
        x = 0
        for tile in layer:
            if tile == '1':
                display.blit(dirt, (x * tile_size, y * tile_size))
            if tile == '2':
                display.blit(grass, (x * tile_size, y * tile_size))
            if tile != '0':
                tile_rects.append(pygame.Rect(x * tile_size, y * tile_size, tile_size, tile_size))
            x += 1
        y += 1

和这个代码的应该是使冲突的工作,但不知怎的,它不,这是在播放器类。

def collisions(self):
    global tile_rects
    self.rect.x += self.x_vel
    self.rect.y += self.y_vel
    for tile_rect in tile_rects:
        if self.rect.colliderect(tile_rect):
            if abs(tile_rect.top - self.rect.bottom) < 10:
                self.y_vel -= 1
            if abs(tile_rect.bottom - self.rect.top) < 10:
                self.y_vel += 1
            if abs(tile_rect.right - self.rect.left) < 10:
                self.x_vel -= 1
            if abs(tile_rect.left - self.rect.right) < 10:
                self.x_vel += 1
    else: tile_rects = []

任何修复?

pygame python
2021-11-23 13:16:31
1

最好的答案

0

你应该使用 collidelistall() 而不是 colliderect(). 它将检查如果rect如果接触任何rect的名单。

2021-11-24 09:24:55

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