最大的一个列表中的蟒蛇recursivly

代码示例

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0

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def maxi(L): # Recursive Boutros
	if len(L) <= 1:
		return L[0]
	else:
		maximum = maxi(L[1:])
		if maximum > L[0]:
			return maximum
        else:
        	return L[0]

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