得到响应html从阿贾克斯

阿贾克斯得到响应html

//your jquery code will be like this:
$.ajax({
      type: 'POST',
      url: $url,
      data: new FormData(this),
      dataType: 'json',
      contentType: false,
      processData:false,//this is a must
      success: function(response){ 
      		$('your_selector').html(response);
      }
});

//php code will be like this
echo '<div>some html code</div>';
die();